Forgotten Tales

3^log(2x)=4x


x=?

(Exact answer, not decimal form)

Term, I genuinely think you have a "math problem" here.

Weget it, Einstein!

madmaniacal1 wrote: ↑Thu Dec 26, 2019 10:36 pm Term, I genuinely think you have a "math problem" here.

hehehe


Ill give you a hint


Since many know the general rule in which log(a^b)=a*log(b) we can see a VERY interesting thing occur if we did this.....

log(a)*log(b)....You can see that in this case it means......log(a)*log(b)=log(a^log(b))=log(b^log(a))....

Which is quite interesting as it leads to this .... log(a^logb)=log(b^loga)....remove log from both sides.....a^logb=b^loga


This will be very helpful in solving this

terminator wrote: ↑Fri Dec 27, 2019 8:05 am

madmaniacal1 wrote: ↑Thu Dec 26, 2019 10:36 pm Term, I genuinely think you have a "math problem" here.

Ill give you a hint

Since many know the general rule in which ....

Hmmmm ... me thinks he doth aßume^² much.